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Wierzycaz
2021-07-31
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Cristiano Sears

Answered 2021-08-01
Author has **96** answers

Given that,

$U=\{10,11,12,13,14,15,16,17,18,19,20\}$

$A=\{10,12,14,16,18,20\}$

$B=\{12,15\}$

$C=\{10,12,14,15,16,18,20\}$

Now,$\left(AUB\right)=\{10,12,14,16,18,20\}U\{12,15\}$

$\left(AUB\right)=\{10,12,14,15,16,18,20\}$

$\Rightarrow \left(AUB\right)\cap C=\{10,12,14,15,16,18,20\}\cap \{10,12,14,15,16,18,20\}$

$\Rightarrow \left(AUB\right)\cap C=\{10,12,14,15,16,18,20\}$

$\Rightarrow n(\left(AUB\right)\cap C)=7$

Hence,$n(\left(AUB\right)\cap C)=7$

Now,

Hence,

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