Let U ={1,2,3,...,2400} Let S be the subset of the numbers in U that are multiples of 3, and let T be the subset of U that are multiples of 7. Since 2400÷3=800, it follows that n(S)=n({3⋅1,3⋅2,⋯,3⋅800})=800. (a) Find n(T) using a method similar to the one that showed that n(S)=800. (b) Find n(S∩T). (c) Label the number of elements in each region of a two-loop Venn diagram with the universe U and subsets S and T. Questions:Find n(T) ? Find n(SnT)

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Let U ={1,​2,3,​...,2400​} Let S be the subset of the numbers in U that are multiples of 3​, and let T be the subset of U that are multiples of 7. Since 2400÷3=800​, it follows that n(S)=n({3⋅1,3⋅2,⋯,3⋅800})=800. ​(a) Find​ n(T) using a method similar to the one that showed that n(S)=800. (b) Find n(S∩T). (c) Label the number of elements in each region of a​ two-loop Venn diagram with the universe U and subsets S and T. Questions:Find n(T) ? Find n(SnT)

Arham Warner · Accepted Answer

Step 1 Solution: n(∪)=2400 ∪={1,2,3,.....,2400} 2400÷3=800 n(s)=n{3⋅1,3⋅2,....3⋅800}=800 n(t)=n(7⋅1,7⋅2,7⋅3,….,7⋅342)=342 2394 Step 2 n(t)=342 s∩t Multiple of 7 and 3=21 n(s∩t)=n(21⋅1,21⋅2,…..21⋅114)=114 2394 n(s∩t)=114

Let\ U = \left\{ 1,2, 3, ...,2400 \right\}Let S be the subset of the numbers in U that are multiples of 3, and let T be the subset of U that are multiples of 7.Find n(T) using a method similar to the one that showed that n(S)=800.

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