# The confidence interval for the mean population is 2.5121 < mu < 2.6879.

The confidence interval for the mean population is $2.5121<\mu <2.6879.$
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odgovoreh
Given:
The total size of the sample of the students is 224 . The meanof the athelatic event participation is 2.6 and the standard deviation is 0.8
Obtain the z- value from the z-table of 90% confidence corresponding to the given mean and standard deviation is 1.645.
The confidence interval for the mean population is calculated as,
$C=\stackrel{^}{x}±z×\frac{s}{\sqrt{n}}$
$=2.6±\left(1.645\right)\frac{0.8}{\sqrt{224}}$
$=2.6±0.0879$
$=2.5121,2.6879$
Thus, the confidence interval for the mean population is $2.5121\le \mu \le 2.6879.$
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