Step 1

The given equation is \(\displaystyle{0.4}{y}-{4}={2}\)

The equation \(\displaystyle{0.4}{y}-{4}={2}\) can be solved as follows.

We multiply the decimal number by 10 to shift the decimal towards right hand side by one place.

Step 2

For clearing the decimals we multiply each term by 10.

\(\displaystyle\Rightarrow{10}\times{0.4}{y}-{10}\times{4}={10}\times{2}\)

\(\displaystyle\Rightarrow{4}{y}-{40}={20}\)

Add both sides by 40.

\(\displaystyle\Rightarrow{4}{y}-{40}+{40}={20}+{40}\)

\(\displaystyle\Rightarrow{4}{y}={60}\)

Divide both sides by 4.

\(\displaystyle\Rightarrow{\frac{{{4}{y}}}{{{4}}}}={\frac{{{60}}}{{{4}}}}\)

\(\displaystyle\Rightarrow\ {y}={15}\)

Therefore, \(\displaystyle{y}={15}\) is the solution of \(\displaystyle{0.4}{y}-{4}={2}.\)

The given equation is \(\displaystyle{0.4}{y}-{4}={2}\)

The equation \(\displaystyle{0.4}{y}-{4}={2}\) can be solved as follows.

We multiply the decimal number by 10 to shift the decimal towards right hand side by one place.

Step 2

For clearing the decimals we multiply each term by 10.

\(\displaystyle\Rightarrow{10}\times{0.4}{y}-{10}\times{4}={10}\times{2}\)

\(\displaystyle\Rightarrow{4}{y}-{40}={20}\)

Add both sides by 40.

\(\displaystyle\Rightarrow{4}{y}-{40}+{40}={20}+{40}\)

\(\displaystyle\Rightarrow{4}{y}={60}\)

Divide both sides by 4.

\(\displaystyle\Rightarrow{\frac{{{4}{y}}}{{{4}}}}={\frac{{{60}}}{{{4}}}}\)

\(\displaystyle\Rightarrow\ {y}={15}\)

Therefore, \(\displaystyle{y}={15}\) is the solution of \(\displaystyle{0.4}{y}-{4}={2}.\)