Suppose that a random sample of 50 bottles of a particular brand of cough syrup is selected and the alcohol content of each bottle is determined. Let

nitraiddQ 2021-02-23 Answered
Suppose that a random sample of 50 bottles of a particular brand of cough syrup is selected and the alcohol content of each bottle is determined. Let j: denote the average alcohol content for the population of all bottles of the brand under study. Suppose that the resulting 95% confidence intervals (7-8, 9.6)
(a) Would 2 90%% confidence interval calculated from this same sample have been narrower or wider than the glven interval? Explain your reasoning.
(b) Consider the following statement: There is 9 95% chance that Is between 7.8 and 9.6. Is this statement correct? Why or why not?
(c) Consider the following statement: We can be highly confident that 95% of al bottles ofthis type of cough syrup have an alcohol content that is between 7.8 and 9.6. Is this statement correct? Why or why not?
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hesgidiauE
Answered 2021-02-24 Author has 106 answers
Given:
The 95% confidence interval of the average alcohol content is (7.8, 9.6)
Sample size (n)=50
a) Confidence level decreased to 90%
Using z tables, the critical value for two tailed 95% confidence interval is 1.96 or 90% is 1.645 If critical value decreases, the margin of error also decreases.
Lets
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