Five people have a genetic disease and one child each. The random variable x is the number of children among the five who inherit the​ disease. a)Find the mean.b)Find the standard deviation.

UkusakazaL

UkusakazaL

Answered question

2021-08-05

Five people have a genetic disease and one child each. The random variable x is the number of children among the five who inherit the​ disease.
a)Find the mean.
b)Find the standard deviation.
x012345P(x)0.0270.1620.3110.3110.1620.027

Answer & Explanation

Ian Adams

Ian Adams

Skilled2021-08-17Added 163 answers

Given:
x012345P(x)0.0270.1620.3110.3110.1620.027
a) μ=xP(x)
=0×0.027+1×0.162+2×0.311+3×0.311+4×0.162+5×0.027
=2.5
b) σ=(xμ)2P(x)
=(02.5)2×0.027+(12.5)2×0.162+(22.5)2×0.311+(32.5)2×0.311+(42.5)2×0.162+(52.5)2×0.027
=1.222
1.1054

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