UkusakazaL
2021-08-01
Answered

If $n=590$ and $p=0.93$ , construct a $90\mathrm{\%}$ confidence interval.

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Khadija Wells

Answered 2021-08-03
Author has **1** answers

Step 1

Express the expression for the confidence interval.

$C.I=p\pm Z\cdot \sqrt{\frac{p(1-p)}{n}}$

Here, Z* is the critical value .

From the Z table, the value corresponding to the region 90.5 is,

$Z\cdot =1.31$

Step 2

Put 590 for n, 0.93 for p, 1.31 for Z* implies,

$C.I=0.93\pm 1.31\sqrt{\frac{0.93(1-0.93)}{0.93}}$

$C.I=0.93\pm 0.346$

Thus, the confidence interval is$0.93+0.346$ and $0.93-0.346$ .

Express the expression for the confidence interval.

Here, Z* is the critical value .

From the Z table, the value corresponding to the region 90.5 is,

Step 2

Put 590 for n, 0.93 for p, 1.31 for Z* implies,

Thus, the confidence interval is

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