Sketch a graph of y = 2x on [-1, 2] and use geometry to find the exact value of function given int_{-1}^{2} 2x dx

Sketch a graph of y = 2x on [-1, 2] and use geometry to find the exact value of function given int_{-1}^{2} 2x dx

Question
Confidence intervals
asked 2021-01-31
Sketch a graph of \(y = 2x on [-1, 2]\) and use geometry to find the exact value of function given
\(\int_{-1}^{2} 2x\ dx\)

Answers (1)

2021-02-01
Let's sketch the graph of the following function:
\(y = 2x\)
on \([-1, 2]\)
image
We can use several methods to find the value of the given expression either by Riemann Sum, or by another sum methods where we need to divide this interval into equal sub-intervals : But we use the easiest method that is we can simply integrate the following expression using the property of integration and then apply the limits:
The given expression is :
\(\int_{-1}^{2} 2x\ dx\)
Let's integrate the following expression:
\(\int_{-1}^{2} 2x\ dx=2\int_{-1}^{2} xdx\)
\(=2[\frac{x^{2}}{2}]_{-1}^{2}\)
\)= [x^{2}]_{-1}^{2}\)
\(= [(2)^{2} - (-1)^{2}]\)
\(= [4 - 1] = 3\) Hence, the value of the given expression is : 3
0

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