A quantity surveyor was asked to study the weight of beef in a particular company. He measured 10 beef pies and their mean weight was 180 g and the standard deviation was 40 g. What is the upper limit of the 95\% confidence interval for the variance of the company (ie upper bound of a 95\% confidence interval for the variance)?

UkusakazaL

UkusakazaL

Answered question

2021-08-03

A quantity surveyor was asked to study the weight of beef in a particular company. He measured 10 beef pies and their mean weight was 180 g and the standard deviation was 40 g. What is the upper limit of the 95% confidence interval for the variance of the company (ie upper bound of a 95% confidence interval for the variance)?
It can be assumed that the weight of the beef follows a normal distribution.
1) 18.93
2) 757.10
3) 5333.33
4) 133.33

Answer & Explanation

Lewis Harvey

Lewis Harvey

Beginner2021-08-09Added 1 answers

Step 1
Given:
n=10
x=180
s=40
α=0.05
t-critical value at 95% confidence and df=9 9s tc=2.262
Step 2
Margin of error (E)=Zc×σn
E=2.262×4010
E=28.61
The 95% confidence is
x±E
Upper limit =x+E
=180+28.61
=208.61

Do you have a similar question?

Recalculate according to your conditions!

New Questions in College Statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?