# Completely simplify the expression (2frac{x}{y^{-1/3}})^{-1} Your final answer should contain no negative exponents and no radicals.

Completely simplify the expression $\left(2\frac{x}{{y}^{-1/3}}{\right)}^{-1}$ Your final answer should contain no negative exponents and no radicals.
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doplovif
For negative in exponent, we can change the side of the term
$\left(2\frac{x}{{y}^{-1/3}}{\right)}^{-1}$
$=\left(2x{y}^{\frac{1}{3}}{\right)}^{-1}$
Then distribute -1 with other exponents
$={2}^{-1}{x}^{-1}\left({y}^{\frac{1}{3}}{\right)}^{1}$
$=\frac{1}{2}\cdot \frac{1}{x}{y}^{-\frac{1}{3}}$
$=\frac{1}{2x{y}^{\frac{1}{3}}}$
Answer: $=\frac{1}{2x{y}^{\frac{1}{3}}}$