Find specific terms of an arithmetic sequence given other terms. How many terms are there in the following finite arithmetic sequence? 7,3,-1,\cdots,-89

Find specific terms of an arithmetic sequence given other terms.
How many terms are there in the following finite arithmetic sequence?
$$\displaystyle{7},{3},-{1},\cdots,-{89}$$
1) 23
2) 24
3) 25
4) 28
5) 30

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Malena
Step 1
Given arithmetic sequence,
$$\displaystyle{7},{3},-{1},\ldots\ldots..,-{89}$$
n-th term formula is:
$$\displaystyle{a}_{{{n}}}={a}_{{{1}}}+{\left({n}-{1}\right)}{d}$$
Where,
$$\displaystyle{a}_{{{1}}}=\text{first term of the sequence}={7}$$
$$\displaystyle{a}_{{{n}}}=\text{last term of the sequence}=-{89}$$
$$\displaystyle{d}=\text{common difference}={\left({a}_{{{2}}}-{a}_{{{1}}}\right)}={\left({3}-{7}\right)}={4}$$
$$\displaystyle{n}=\text{number of terms}=?$$
Step 2
Substitute all values in the formula and solve for n,
$$\displaystyle-{89}={7}+{\left({n}-{1}\right)}{\left(-{4}\right)}$$
$$\displaystyle-{89}-{7}=-{4}{\left({n}-{1}\right)}$$
$$\displaystyle-{96}=-{4}{\left({n}-{1}\right)}$$
$$\displaystyle{\left({n}-{1}\right)}={\frac{{{\left(-{96}\right)}}}{{{\left(-{4}\right)}}}}$$
$$\displaystyle{\left({n}-{1}\right)}={24}$$
$$\displaystyle{n}={25}$$
Therefore, there are 25 terms in the sequence.