Step 1

Remember that regression analysis is the process of looking for a best fit of model for a set of data. This can be done on a graphing utility as follows:

1. Press [STAT], the input corresponging x-values of data in L1, and y-values of data in L2.

2. Use [STATPLOT] to observe a scatterplot of the data.

3. Press [STAT], then [CALC] then [ExpReg]/[LnReg]/[Logistic].

This will show you a function in either the form of an exponential, a logarithmic or a logistic model.

4. Graph this equation on the same window as the scatterplot to see if it fits the data.

Step 2

1. Press [STAT], the input corresponging x-values of data in L1, and y-values of data in L2.

2. Use [STATPLOT] to observe a scatterplot of the data.

Based on the plots of the points, it can be exponential or logarithmic.

However, upon checking both regression analysis, the one with the closest value of \(\displaystyle{r}^{{{2}}}\) to 1 is exponential, hence, its formula is \(\displaystyle{y}={\frac{{{18.41663}}}{{{1}+{7.54619}{e}^{{-{0.68374}{x}}}}}}\) The graph of which is below:

Answer:\(\displaystyle{y}={\frac{{{18.41663}}}{{{1}+{7.54619}{e}^{{-{0.68374}{x}}}}}}\)