The variable z is often used to denote a complex number and z¯ is used to denote its conjugate. If z = a+bi, simplify the expression z^{2}-\overline{z

emancipezN 2021-07-02 Answered

The variable z is often used to denote a complex number and \(\bar{z}\) is used to denote its conjugate. If \(z = a+bi,\) simplify the expression
\(\displaystyle{z}^{{{2}}}-\overline{{{z}}}^{{{2}}}\)

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Expert Answer

Benedict
Answered 2021-07-03 Author has 27710 answers

With z=a+bi, the conjugate, \(\displaystyle\overline{{z}}\), is a-bi. Hence, the expression \(\displaystyle{z}^{{{2}}}-\overline{{{z}}}^{{{2}}}\), is equivalent to
\(\displaystyle{\left({a}+{b}{i}\right)}^{{{2}}}-{\left({a}-{b}{i}\right)}^{{{2}}}={\left[{\left({a}\right)}^{{{2}}}+{2}{\left({a}\right)}{\left({b}{i}\right)}^{{{2}}}\right]}-{\left[{\left({a}\right)}^{{{2}}}-{2}{\left({a}\right)}{\left({b}{i}\right)}+{\left({b}{i}\right)}^{{{2}}}\right]}\)
\(\displaystyle{\left({u}{s}{e}{\left({a}+{b}\right)}^{{{2}}}={\left({a}\right)}^{{{2}}}+{2}{\left({a}\right)}{\left({b}\right)}+{\left({b}\right)}^{{{2}}}\right)}\)
\(\displaystyle={\left[{a}^{{{2}}}+{2}{a}{b}{i}+{b}^{{{2}}}{i}^{{{2}}}\right]}-{\left[{a}^{{{2}}}-{2}{a}{b}{i}+{b}^{{{2}}}{i}^{{{2}}}\right]}={a}^{{{2}}}+{2}{a}{b}{i}+{b}^{{{2}}}{i}^{{{2}}}-{a}^{{{2}}}+{2}{a}{b}{i}-{b}^{{{2}}}{i}^{{{2}}}={\left({a}^{{{2}}}-{a}^{{{2}}}\right)}+{\left({2}{a}{b}{i}+{2}{a}{b}{i}\right)}+{\left({b}^{{{2}}}{i}^{{{2}}}-{b}^{{{2}}}{i}^{{{2}}}\right)}={0}+{4}{a}{b}{i}+{0}={\left({4}{a}{b}{i}\right)}{i}\).
Hence, \(z^{2}-\overline{z}^{2}=(4abi)i\).

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