Question

Find the derivatives of the given functions. h(x)=2\sec x+3\tan x+3x

Derivatives
ANSWERED
asked 2021-06-30
Find the derivatives of the given functions. \(\displaystyle{h}{\left({x}\right)}={2}{\sec{{x}}}+{3}{\tan{{x}}}+{3}{x}\)

Answers (1)

2021-07-01
\(\displaystyle{h}{\left({x}\right)}={2}{\sec{{x}}}+{3}{\tan{{x}}}+{3}{x}\)
\(\displaystyle{h}'{\left({x}\right)}={\frac{{{d}}}{{{\left.{d}{x}\right.}}}}{\left({2}{\sec{{x}}}+{3}{\tan{{x}}}+{3}{x}\right)}\)
\(\displaystyle={\frac{{{d}}}{{{\left.{d}{x}\right.}}}}{\left({2}{\sec{{x}}}\right)}+{\frac{{{d}}}{{{\left.{d}{x}\right.}}}}{\left({3}{\tan{{x}}}\right)}+{\frac{{{d}}}{{{\left.{d}{x}\right.}}}}{\left({3}{x}\right)}\)
\(\displaystyle={2}{\sec{{x}}}{\tan{{x}}}+{3}{{\sec}^{{{2}}}{x}}+{3}\)
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