# If you have a 99% confidence interval for μμ based on a simple random sample, is it correct to say that in the long run, if you computed many, many co

If you have a 99% confidence interval for $$\mu;\mu$$; based on a simple random sample, is it correct to say that in the long run, if you computed many, many confidence intervals using the prescribed method, about 99% of such intervals would contain $$\mu$$;? Explain.

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averes8
Yes, because in 99% of all possible sample of sample size n, the 99% confidence interval will contain $$\displaystyle\mu$$.