6 of the 10 integers between 1 and 10 inclusive are more than 4 (that is, 5,6,7,8,9,10).
The probability is the number of favorable outcomes divided by the number of possible outcomes:
5 of the 10 integers between 1 and 10 inclusive are odd (that is, 1,3,5,7,9). P(odd)=# of favorable outcomes/# of possible outcomes=
3 of the 10 integers between 1 and 10 inclusive are move than 4 and odd (that is, 5,7,9).
Use the General addition rule for any two events:
P(>4 or odd)