Suppose you ask a friend to randomly choose an integer between 1 and 10, inclusive. What is the probability that the number will be more than 4 or odd

vazelinahS 2021-06-24 Answered
Suppose you ask a friend to randomly choose an integer between 1 and 10, inclusive. What is the probability that the number will be more than 4 or odd? (Enter your probability as a fraction.)
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Expert Answer

Brittany Patton
Answered 2021-06-25 Author has 100 answers

6 of the 10 integers between 1 and 10 inclusive are more than 4 (that is, 5,6,7,8,9,10).
The probability is the number of favorable outcomes divided by the number of possible outcomes: P(>4)=#of favorable outcomes # of possible outcomes=610
5 of the 10 integers between 1 and 10 inclusive are odd (that is, 1,3,5,7,9). P(odd)=# of favorable outcomes/# of possible outcomes=510
3 of the 10 integers between 1 and 10 inclusive are move than 4 and odd (that is, 5,7,9). P(>4 and odd)=# of favorable outcomes/# of possible outcomes=310
Use the General addition rule for any two events: P(AUB)=P(A)+P(B)P(AB)
P(>4 or odd) =P(>4)+P(odd)P(>4and odd)=610+510310=6+5310=810=45

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