We are given the function:
\(y=0.1*2^x\)

The function is of exponential growth because it is in the form: \(y=a(1+r)^x\), r>0

We find the growth factor: 1+r=2

r=2-1

r=1=100%

The function is of exponential growth because it is in the form: \(y=a(1+r)^x\), r>0

We find the growth factor: 1+r=2

r=2-1

r=1=100%