# (x/4)+(1/2)=1/8

$$\displaystyle{\left(\frac{{x}}{{4}}\right)}+{\left(\frac{{1}}{{2}}\right)}=\frac{{1}}{{8}}$$

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Bentley Leach

We are given: $$(\frac{x}{4})+(\frac{1}{2})=\frac{1}{8}$$
Multiply both sides by the LCD which is 8: $$((\frac{x}{4})+(\frac{1}{2}))(8)=\frac{1}{8}(8)$$
$$2x+4=1$$
Subtract 4 from both sides: $$2x+4-4=1-4$$
$$2x=-3$$
Divide both sides by 2: $$\frac{2x}{2}=-\frac{3}{2}$$
$$x=-(\frac{3}{2})$$