Question

# The college physical education department offered an advanced first aid course last semester. The scores on the comprehensive final exam were normally

Normal distributions
The college physical education department offered an advanced first aid course last semester. The scores on the comprehensive final exam were normally distributed, and the z scores for some of the students are shown below: Robert, 1.10 Juan, 1.70 Susan, -2.00 Joel, 0.00 Jan, -0.80 Linda, 1.60 If the mean score was &mu;=150&mu;=150 with standard deviation &sigma;=20,&sigma;=20, what was the final exam score for each student?

2021-07-02
Given: μ= 150
σ=20
The final exam scoreis the mean increased by the product of the z-score and the standard deviation, since the z-score measures the number of standard devintions that the value is from the mean:
Robert: x = μ + zσ = 150 + 1.10(20) = 172
Joel: x = μ + zσ = 150 + 0.00(20) = 150
Juan: x = μ + zσ = 150 + 1.70(20) = 184
Jan: x = μ + zσ = 150 — 0.80(20) = 134
Susan: x = μ + zσ = 150 — 2.00(20) = 110
Linda: x = μ + zσ = 150 + 1.60(20) = 182