# Suppose you ask a friend to randomly choose an integer between 1 and 10, inclusive. What is the probability that the number will be more than 4 or odd

Suppose you ask a friend to randomly choose an integer between 1 and 10, inclusive. What is the probability that the number will be more than 4 or odd? (Enter your probability as a fraction.)
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Arnold Odonnell

6 of the 10 integers between 1 and 10 inclusive are more than 4 (that is, 5,6,7,8,9,10).
The probability is the number of favorable outcomes divided by the number of possible outcomes: $P\left(>4\right)=$=$\frac{6}{10}$
5 of the 10 integers between 1 and 10 inclusive are odd (that is, 1,3,5,7,9). P(odd)==$\frac{5}{10}$
3 of the 10 integers between 1 and 10 inclusive are move than 4 and odd (that is, 5,7,9). $P\left(>4$ and odd)==$\frac{3}{10}$
Use the General addition rule for any two events: $P\left(AUB\right)=P\left(A\right)+P\left(B\right)-P\left(A\bigcap B\right)$