By cofunction identities, \(\tan\theta=\cot(90^{\circ}-\theta)\)

Hence,

\(\tan28^{\circ}=\cot(90^{\circ}-28^{\circ})=\cot62^{\circ}\)

Question

asked 2021-06-01

\(\tan \theta \cot \theta = 1\)

asked 2021-02-09

asked 2021-05-14

asked 2021-01-04

\(\sec \theta = -3, \tan \theta > 0\). Find the exact value of the remaining trigonometric functions of

\(\theta\).