 # One type of Iodine disintegrates continuously at a constant rate of 8.6% per day. Suppose the original amount,P_0, is 10 grams, and let be measured in OlmekinjP 2021-02-10 Answered
One type of Iodine disintegrates continuously at a constant rate of 8.6% per day. Suppose the original amount,${P}_{0}$, is 10 grams, and let be measured in days. Because the Iodine is decaying continuously at a constant rate, we use the model $P={P}_{0}{e}^{kt}$ for the decay equation, where k is the rate of continuous decay. Using the given information, write the decay equation for this type of Iodine.
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The model of the decay equation is given by $P={P}_{0}{e}^{kt}$ Here ${P}_{0}=10$ grams of iodine $k=\text{rate of continuous rate}=-8.6$ { negative sign implies the decay} Which implies $k=-0.086$ t is measured in days Therefore, the decay equation for this type of Iodine is $P=10{e}^{-0.086t}$