One type of lodine disintegrates continuously at a constant rate of 8.6% per day. Suppose the original amount, P0, is 10 grams, and let be measured in

Question

One type of lodine disintegrates continuously at a constant rate of 8.6% per day. Suppose the original amount, P0, is 10 grams, and let be measured in days. Because the lodine is decaying continuously at a constant rate, we use the model P = P0e for the decay equation, where k is the rate of continuous decay. Using the given information, write the decay equation for this type of lodine.

Answer 1

The model of the decay equation is given by $P = P_{0} e : (k t)$ Here $P_{0} = 10$ grams of iodine $k = r a t e o f c o n t i n u o u s r a t e = - 8.6$ { negative sign implies the decay} Which implies $k = - 0.086$ t is measured in days Therefore, the decay equation for this type of Iodine is

One type of lodine disintegrates continuously at a constant rate of 8.6% per day. Suppose the original amount, P0, is 10 grams, and let be measured in

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