One type of lodine disintegrates continuously at a constant rate of 8.6% per day. Suppose the original amount, P0, is 10 grams, and let be measured in

kuCAu

kuCAu

Answered question

2020-10-20

One type of lodine disintegrates continuously at a constant rate of 8.6% per day. Suppose the original amount, P0, is 10 grams, and let be measured in days. Because the lodine is decaying continuously at a constant rate, we use the model P = P0e for the decay equation, where k is the rate of continuous decay. Using the given information, write the decay equation for this type of lodine.

Answer & Explanation

saiyansruleA

saiyansruleA

Skilled2020-10-21Added 110 answers

The model of the decay equation is given by P=P0e:(kt) Here P0=10 grams of iodine k=rate of continuous rate=8.6 { negative sign implies the decay} Which implies k=0.086 t is measured in days Therefore, the decay equation for this type of Iodine is

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?