The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution,

Chesley 2021-05-03 Answered

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent. [1200|40010|30001|20000|0]

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Bella
Answered 2021-05-04 Author has 81 answers

There are no impossible equations, such as (0=1), the system is consistent,
One variables does not have a leading 1 in its corresponding column, so we take it as a parameter ... the system is consistent and has infinitely many solutions.
Parameters: x2R
Interpreting row by row as equations.

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