\(\displaystyle{V}=π{r}^{{2}}{h}\)

\(\displaystyle{120}=π{\left({1.5}\right)}^{{2}}{h}\)

\(\displaystyle\frac{{120}}{{π{\left({1.5}\right)}^{{2}}}}={h}\)

17.0 ~ h

From part a), the volume of the cube is \(\displaystyle{120}\in^{{3}}\)

Let the volume of the cylinder by \(\displaystyle{V}={120}\in^{{3}}\)

The diameter of the cylinder is d=3 inches so the radius is \(\displaystyle{r}=\frac{{d}}{{2}}=\frac{{3}}{{2}}={1.5}\) inches. Substitute the volume and radius into the formula for the volume to evaluate and round to the nearest tenth.

\(\displaystyle{120}=π{\left({1.5}\right)}^{{2}}{h}\)

\(\displaystyle\frac{{120}}{{π{\left({1.5}\right)}^{{2}}}}={h}\)

17.0 ~ h

From part a), the volume of the cube is \(\displaystyle{120}\in^{{3}}\)

Let the volume of the cylinder by \(\displaystyle{V}={120}\in^{{3}}\)

The diameter of the cylinder is d=3 inches so the radius is \(\displaystyle{r}=\frac{{d}}{{2}}=\frac{{3}}{{2}}={1.5}\) inches. Substitute the volume and radius into the formula for the volume to evaluate and round to the nearest tenth.