\(foci\ = (h\ \pm\ ae,\ k)\)

\((1, \pm\ 5,\ 2)\)

\((6,\ 2)\ (−4,\ 2)\)

\(vertices\ = (h\ \pm\ a,\ k)\ (h\ \pm\ k,\ b)\)

\((1\ \pm\ 4,\ 2)\ (1\ \sqrt{2\ \pm,\ 3})\)

\((5,\ 2)(−3,\ 2)\ (1,\ 1)(1,\ −5)\)

\(\frac{major\ axis}{minor\ axis}=8\ +\ 6\)

lamusesamuset

Answered 2021-01-26
Author has **27637** answers

\(foci\ = (h\ \pm\ ae,\ k)\)

\((1, \pm\ 5,\ 2)\)

\((6,\ 2)\ (−4,\ 2)\)

\(vertices\ = (h\ \pm\ a,\ k)\ (h\ \pm\ k,\ b)\)

\((1\ \pm\ 4,\ 2)\ (1\ \sqrt{2\ \pm,\ 3})\)

\((5,\ 2)(−3,\ 2)\ (1,\ 1)(1,\ −5)\)

\(\frac{major\ axis}{minor\ axis}=8\ +\ 6\)

asked 2021-08-08

Find the equation of the graph for each conic in general form. Identify the conic, the center, the vertex, the co-vertex, the focus (foci), major axis, minor axis, \(\displaystyle{a}^{{2}}\), \(\displaystyle{b}^{{2}}\), and \(\displaystyle{c}^{{2}}\). For hyperbola,find the asymtotes.Sketch the graph

\(\displaystyle{9}{\left({y}-{3}\right)}^{{2}}-{4}{\left({x}+{5}\right)}^{{2}}={36}\)

\(\displaystyle{9}{\left({y}-{3}\right)}^{{2}}-{4}{\left({x}+{5}\right)}^{{2}}={36}\)

asked 2020-12-27

asked 2020-12-24

For Exercise,

a. Identify the equation as representing a circle, an ellipse, a hyperbola, or a parabola.

b. Graph the curve. c. Identify key features of the graph. That is. If the equation represents a circle, identify the center and radius.

If the equation represents an ellipse, identify the center, vertices, endpoints of the minor axis, foci, and eccentricity.

If the equation represents a hyperbola, identify the center, vertices, foci, equations of the asymptotes, and eccentricity.

If the equation represents a parabola, identify the vertex, focus, endpoints of the latus rectum, equation of the directrix, and equation of the axis of symmetry. \(x^2\ +\ y^2\ −\ 4x\ −\ 6y\ +\ 1 = 0\)

asked 2020-11-23

asked 2021-08-14

\(\displaystyle{5}{x}^{{2}}+{4}{x}{y}+{2}{y}^{{2}}-{\frac{{{28}}}{{\sqrt{{5}}}}}{x}-{\frac{{{4}}}{{\sqrt{{5}}}}}{y}+{4}={0}\)

asked 2021-01-15

asked 2021-08-11

Find the vertices and foci of the conic section. \(\frac{x^2}{4 }− \frac{y^2}{9} = 36\)