Substitute P=3000, r=0.06 (for 6%), n=4, and t=7: \(\displaystyle{A}={3000}{\left({1}+\frac{{0.06}}{{4}}\right)}^{{4}}{\left({7}\right)}\)

\(\displaystyle{A}={3000}{\left({1.015}\right)}^{{28}}\)

A ~ $4551.67

Use the continuos compounding interest formula: \(\displaystyle{A}={P}{c}^{{r}}{t}\)

where A is the final value, P is the present value, r is the rate (in decimal form), and t is the time in years.

Substitute P=3000, r=0.06 (for 6%), and t=7: \(\displaystyle{A}={3000}{c}^{{{0.06}}}{\left({7}\right)}\)

\(\displaystyle{A}={3000}{c}^{{0.42}}\)

A ~ $4365.88