1/(secθ-tanθ)+1/(secθ+tanθ)

Aneeka Hunt

Aneeka Hunt

Answered question

2021-05-30

1secθtanθ+1secθ+tanθ

 

Answer & Explanation

Isma Jimenez

Isma Jimenez

Skilled2021-05-31Added 84 answers

We are given: 1secθtanθ+1secθ+tanθ

 

Rewrite using the LCD which is(secθtanθ)(secθ+tanθ)=1secθtanθsecθ+tanθsecθ+tanθ+1secθ+tanθsecθtanθsecθtanθ=(secθ+tanθ)+(secθtanθ)sec2θtan2θ

 

Recall that sec2θ=1+tan2θsosec2θtan2θ=1=2secθ1=2secθ

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