Equations of conic sections, Systems of Non-linear Equations illustrate a series, differentiate a series from a sequence Determine the first five term

Given that, $n^{th}\text{term of the sequence is}{3}^{n+1}.$ Take $n=0$ $a_n=3^{n+1}$
$a_0=3^{0+1}=3$ Therefore, the first term is 3. Take $n=1,$
$a_1=3^{1+1}$
$a_1=3^{1+1}=3^2=9$ The second term is 9 Take $n=2,$
$a_2=3^{2+1}$
$=3^3$
$a_2=27$ The third term is 27 For, $n=3,$
$a_3=3^{3+1}$
$=3^4$
$a^3=81$ Fourth term is 81 For, $n=4,$
$a_4=3^{4+1}$
$=3^5$
$a^4=243$ Fifth term is 243. Therefore, the first 5 terms of the sequence are $3,9,27,81,243.$ Step 3 The given sequence is $3,9,27,81,243.$ The series associated with the given sequence is $\sum _{n=0}^5{3}^{n+1}=3+9+27+81+23$
$\sum _{n=0}^5{3}^{n+1}=363$