Given:

\(Wham(x)= x\times x\)

\(Wham(X,Y) = Wham(X)+ Wham(Y)\)

We need to evaluate \(Wham((2,4),(7,9)).\)

\(Wham(X,Y) = Wham(X)+ Wham(Y)\)

\(Wham((2,4), (7,9)) = Wham(2,4) + Wham(7,9)\)

\(Wham(X,Y) = Wham(X)+ Wham(Y) = Wham(2)+ Wham(4) + Wham(7)+ Wham(9)\)

\(Wham(z) = x\times x =\displaystyle{2}\cdot{2}+{4}\cdot{4}+{7}\cdot{7}+{9}\cdot{9} =4+16+49+81 =150\)