It is given that for every 140 cars sold, 23 will be brought back to the dealer for major repairs.
That means, the percentage of cars brought back for major repairs is
\(\displaystyle\frac{{23}}{{140}}\)

It si also given that the dealer sells 980 cars this year. We have to find (approximately) how many cars will be brought back for major repairs?

Let x be the number of cars that will be brought back for major repairs this year.. Thus the perccentage of cars will be brought back for major repair is. \(\displaystyle\frac{{x}}{{980}}\)

As we are assuming that the same percentage of cars will be brought back for major repairs, that means, we can write the proportion: \(\displaystyle\frac{{23}}{{140}}=\frac{{x}}{{980}}\)

On multiply both sides by 980 we get \(\displaystyle{x}=\frac{{{23}\cdot{980}}}{{140}}=\frac{{22540}}{{140}}={161}\)

Thus this year 161 cars bring back for major repairs

It si also given that the dealer sells 980 cars this year. We have to find (approximately) how many cars will be brought back for major repairs?

Let x be the number of cars that will be brought back for major repairs this year.. Thus the perccentage of cars will be brought back for major repair is. \(\displaystyle\frac{{x}}{{980}}\)

As we are assuming that the same percentage of cars will be brought back for major repairs, that means, we can write the proportion: \(\displaystyle\frac{{23}}{{140}}=\frac{{x}}{{980}}\)

On multiply both sides by 980 we get \(\displaystyle{x}=\frac{{{23}\cdot{980}}}{{140}}=\frac{{22540}}{{140}}={161}\)

Thus this year 161 cars bring back for major repairs