x+y+2z=33x+2y+2z=4x+y+3z=5

Kye

Kye

Answered question

2021-06-23

x+y+2z=3
3x+2y+2z=4
x+y+3z=5

Answer & Explanation

sovienesY

sovienesY

Skilled2021-06-24Added 89 answers

"We are given: x+y+2z=3
3x+2y+2z=4
x+y+3z=5
Subtract (1) and (3) to eliminate x and y and solve for z: z=2
z=2
Substitute z=2 to (1) and simplify to obtain (4): x+y+2(2)=3
x+y=1
Substitute z=2 to (2) and simplify to obtain (5): 3x+2y+2(2)=4
3x+2y=0
Multiply (4) by 2 to obtain (6): 2x+2y=2
Subtract (5) and (6) to eliminate 2y and solve for x: x=2
Solve for y using (4): 2+y=1
y=3
So, the solution of the system is: (x,y,z)=(2,3,2)

2022-01-14

7) solve the linear system   2x-2y+z=3

  3x-y-z=7

    x-3y+2z=0

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