Question

# The line with y-intercept 4 and perpendicular to x+5y=8

Probability and combinatorics
The line with y-intercept 4 and perpendicular to x+5y=8

Two lines are perpendicular if their slope are negative reciprocals. Given that the line must be perpendicular to x+5y=8 or $$\displaystyle{y}=-{\left(\frac{{1}}{{5}}\right)}{x}+\frac{{8}}{{5}}$$, then the slope of the required is: m=5