We are given: \(\displaystyle{\left(-{3}{j}^{{-{{5}}}}\cdot{k}^{{6}}\right)}^{{4}}\)

Use the rules: \(\displaystyle{\left({a}{b}\right)}^{{n}}={a}^{{n}}\cdot{b}^{{n}}\) and \((a^m)^n=a^{mn} =(-3)^4\times j^{-20}\times k^{24} =81j^{-20}\times k^{24}\)

Use the negative exponent rule: \(a^-n=\frac{1}{a^n} =\frac{81k^{24}}{j^{20}}\)