Question

(-3j^-5*k^6)^4

Probability and combinatorics
ANSWERED
asked 2021-07-03
\(\displaystyle{\left(-{3}{j}^{{-{{5}}}}\cdot{k}^{{6}}\right)}^{{4}}\)

Answers (1)

2021-07-04

We are given: \(\displaystyle{\left(-{3}{j}^{{-{{5}}}}\cdot{k}^{{6}}\right)}^{{4}}\)
Use the rules: \(\displaystyle{\left({a}{b}\right)}^{{n}}={a}^{{n}}\cdot{b}^{{n}}\) and \((a^m)^n=a^{mn} =(-3)^4\times j^{-20}\times k^{24} =81j^{-20}\times k^{24}\)
Use the negative exponent rule: \(a^-n=\frac{1}{a^n} =\frac{81k^{24}}{j^{20}}\)

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