Question

(7w^2+6wz+4z^2)−(w^2−3wz+2z^2)

Probability and combinatorics
ANSWERED
asked 2021-06-15
\(\displaystyle{\left({7}{w}^{{2}}+{6}{w}{z}+{4}{z}^{{2}}\right)}−{\left({w}^{{2}}−{3}{w}{z}+{2}{z}^{{2}}\right)}\)

Answers (1)

2021-06-16
We are given: \(\displaystyle{\left({7}{w}^{{2}}+{6}{w}{z}+{4}{z}^{{2}}\right)}−{\left({w}^{{2}}−{3}{w}{z}+{2}{z}^{{2}}\right)}\)
Distribute the negative: \(\displaystyle={7}{w}^{{2}}+{6}{w}{z}+{4}{z}^{{2}}−{w}^{{2}}−{3}{w}{z}+{2}{z}^{{2}}\)
Combine like terms: \(\displaystyle={6}{w}^{{2}}+{9}{w}{z}+{2}{z}^{{2}}\)
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