# Solve for y: (7y+3)/2=((8y+1)/6)+23 Simplify your answer as much as possible.

Solve for y: $\frac{7y+3}{2}=\left(\frac{8y+1}{6}\right)+23$
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Liyana Mansell
We are given: $\frac{7y+3}{2}=\left(\frac{8y+1}{6}\right)+23$
Multiply both sides by the LCD which is 6: $\frac{7y+3}{2}\left(6\right)=\left(\left(\frac{8y+1}{6}\right)+23\right)\left(6\right)$
21y+9=(8y+1)+138
21y+9=8y+139
Subtract 9 from both sides: 21y=8y+130
Subtract 8y from both sides: 13y=130
Divie both sides by 13: y=10
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