y=x^2-12x Form Vertex: Axis: Domain: Range:

Reggie 2021-05-23 Answered
\(\displaystyle{y}={x}^{{2}}-{12}{x}\)
Form
Vertex:
Axis:
Domain:
Range:

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Expert Answer

AGRFTr
Answered 2021-05-24 Author has 12717 answers

Domain of \(\displaystyle{x}^{{2}}-{12}{x}\):

Solution:\(\displaystyle-∞{<}{x}{<}∞\) ;

Interval Notation: \(\displaystyle{\left(-∞,∞\right)}\)

Range of \(\displaystyle{x}^{{2}}-{12}{x}\):

Solution: \(\displaystyle{f{{\left({x}\right)}}}\Rightarrow-{36};{\left[-{36},∞\right)}\)

Axis interception points of \(\displaystyle{x}^{{2}}-{12}{x}\):

X-Intercepts: (12,0),(0,0),

Y-Intercepts: (0,0)

Vertex of \(\displaystyle{x}^{{2}}-{12}{x}\)

Vertex form is: \(\displaystyle{y}={\left({x}-{6}\right)}^{{2}}-{36}\)

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