Parametric equations and a value for the parameter t are given x = (60 cos 30^{circ})t, y = 5 + (60 sin 30^{circ})t - 16t2, t = 2. Find the coordinates of the point on the plane curve described by the parametric equations corresponding to the given value of t.

slaggingV 2021-03-01 Answered
Parametric equations and a value for the parameter t are given x=(60cos30)t,y=5+(60sin30)t16t2,t=2. Find the coordinates of the point on the plane curve described by the parametric equations corresponding to the given value of t.
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Expert Answer

Laith Petty
Answered 2021-03-02 Author has 103 answers

Step 1 Given Parametric equations and a value for the parameter t x=(60cos30)t,y=5+(60sin30)t16t2 and t=2 We have to find the coordinates of the point on the plane curve described by the parametric equations corresponding to the given value of t. Step 2 Given parametric equation x=(60cos30)t,y=5+(60sin30)t16t2 As cos 30=32 and sin30=12 So, x=(303)t,y=5+30t16t2 (1) Now we have to find the coordinates of the point on the plane curve corresponding to the value t=2. On plugging in t=2 in (1) we get:x=603,y=1 So, (603,1) is the point.

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