Solve {(x-3)^2+(y+1)^2=5; x-3y=7}

Burhan Hopper

Burhan Hopper

Answered question

2021-05-16

Solve {(x3)2+(y+1)2=5x3y=7

Answer & Explanation

liingliing8

liingliing8

Skilled2021-05-17Added 95 answers

Let:
(x3)2+(y+1)2=5(1)
x3y=7
Use substitution. Solve for x using (2) to obtain (3):
x=3y+7(3)
Substitute (3) to (1) and solve for y:
(3y+73)2+(y+1)2=5
(3y+4)2+(y+1)2=5
(9y2+24y+16)+(y2+2y+1)=5
10y2+26y+17=5
10y2+26y+12=0
Factor:
2(5y2+13y+6)=0
2(y+2)(5y+3)=0
By zero product property,
y=2,35
Solve for the corresponding xx values using (3).
When y=2y=2,
x=3(2)+7
x=1
When y=35,
x=3(35)+7
x=265
So, the solutions are:
(1,2) and (265,35)

Jeffrey Jordon

Jeffrey Jordon

Expert2021-08-11Added 2605 answers

Answer is given below (on video)

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?