Inverse Trigonometric Forms (92):

Nann
2021-05-14
Answered

Use the Table of Integrals to evaluate the integral. (Use C for the constant of integration.)

$\int 37{e}^{74x}\mathrm{arctan}({e}^{37x})dx$

Inverse Trigonometric Forms (92):$\int u{\mathrm{tan}}^{-1}u\text{}du=\frac{{u}^{2}+1}{2}{\mathrm{tan}}^{-1}u-\frac{u}{2}+C$

Inverse Trigonometric Forms (92):

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curwyrm

Answered 2021-05-15
Author has **87** answers

Step 1

From table given formula number 92:

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