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insonsipthinye

Answered 2021-05-13
Author has **19337** answers

asked 2021-11-16

Find the area of the region enclosed by one loop of the curve. \(\displaystyle{r}={\sin{{4}}}\theta\)

asked 2021-09-15

Find the area of the region that lies inside both curves. \(\displaystyle{r}=\sqrt{{3}}{\cos{\theta}},{r}={\sin{\theta}}\)

asked 2021-06-11

Use a double integral to find the area of the region. The region inside the cardioid \(r=1+\cos \theta\) and outside the circle \(r=3 \cos \theta\)

asked 2021-05-31

Find the area enclosed by the curve

\(x = t^2 - 2t, y = \sqrt{1}t\) and the y-axis.

\(x = t^2 - 2t, y = \sqrt{1}t\) and the y-axis.

asked 2021-02-17

A square loop of copper wire is initially placed perpendiclar to the lines of a constant magnetic field of \(\displaystyle{5}\times{10}^{{3}}\) T.The area enclosed by the loop is 0.2 square meter. the loopis then turned through an angle \(\displaystyle{90}^{\circ}\) so thatthe plane of the loop is parallel to the field lines. the turntakes 0.1 second. what is the average emf induced in the loop during the turn?

asked 2021-09-02

Use a double integral to find the area of the region. The region inside the circle \(\displaystyle{\left({x}-{5}\right)}^{{2}}+{y}^{{2}}={25}\) and outside the circle \(\displaystyle{x}^{{2}}+{y}^{{2}}={25}\)

asked 2021-06-06

Use a double integral to find the area of the region. The region inside the circle \((x - 5)^2 + y^2 = 25\) and outside the circle \(x^2 + y^2 = 25\)