Question

asked 2021-06-03

Find the exact length of the curve. \(x = \frac{y^4}{8} + \frac{1}{4y^2} , 1 \leq y \leq 2\)

asked 2021-05-08

\(x =\sin \left(\frac{\theta}{2}\right), y = \cos \left(\frac{\theta}{2}\right), -\pi \leq \theta \leq \pi\) (a) Eliminate the parameter to find a Cartesian equation of the curve. and how does thecurve look

asked 2021-05-18

Find the exact length of the curve

\(x=\frac{y^4}{8}+\frac{1}{4y^2}\quad1\leq y\leq2\)

\(x=\frac{y^4}{8}+\frac{1}{4y^2}\quad1\leq y\leq2\)

asked 2021-06-07

Evaluate the line integral

\(\int_c xyds\)

Where c is the given curve

\(c:x=t^2,y=2t,0\leq t\leq5\)

\(\int_c xyds\)

Where c is the given curve

\(c:x=t^2,y=2t,0\leq t\leq5\)