Find the exact length of the curve. x = \frac{y^4}{8} + \frac{1}{4y^2} , 1 \leq y \leq 2

Suman Cole 2021-06-03 Answered
Find the exact length of the curve. \(x = \frac{y^4}{8} + \frac{1}{4y^2} , 1 \leq y \leq 2\)

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Expert Answer

Arnold Odonnell
Answered 2021-06-04 Author has 18084 answers
The answer to your question is pretty simple:

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