Question

Find the exact length of the curve. x = \frac{y^4}{8} + \frac{1}{4y^2} , 1 \leq y \leq 2

Integrals
ANSWERED
asked 2021-06-03
Find the exact length of the curve. \(x = \frac{y^4}{8} + \frac{1}{4y^2} , 1 \leq y \leq 2\)

Answers (1)

2021-06-04
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