Diagonalize the following matrix. The real eigenvalues are given to the right of the matrix. \begin{bmatrix}2 & 5&5 \\5 & 2&5\\5&5&2 \end{bmatrix}\lambda=-3.12 Find P and D

Caelan

Caelan

Answered question

2021-05-03

Diagonalize the following matrix. The real eigenvalues are given to the right of the matrix.
[255525552]λ=3.12
Find P and D

Answer & Explanation

Luvottoq

Luvottoq

Skilled2021-05-04Added 95 answers

Solution to your matrix:

image
image

Jeffrey Jordon

Jeffrey Jordon

Expert2021-09-09Added 2605 answers

λ= Eigen values

* Eigen vectors form λ=12

AλI=[2λ5552λ555212]=[212555212555212]=[105551055510]

[10550151501515][1055055000]

[10010055000][101011000]

So (AλI)x=0

[101011000][x1x2x3]=[000]

x1x3=0; x1=x3

x2x3=0; x2=x3

So x=[x1x2x3]=[x3x3x3]=x3[111] So x=[111]

Then find Eigen vectors v2 form λx=3

AλI=[2(3)5552(3)5552(3)]=[555555555][555000000][111000000]

So (AλI)x=0

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