Find an equation of the plane tangent to the following surface at the given point. 7xy+yz+4xz-48=0;\ (2,2,2)

geduiwelh 2021-06-04 Answered
Find an equation of the plane tangent to the following surface at the given point.
7xy+yz+4xz48=0; (2,2,2)
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Expert Answer

Usamah Prosser
Answered 2021-06-05 Author has 86 answers
f(x,y,z)=7xy+yz+4xz48=0 (2,2,2)
Tangent direction is (Px,Py,Pz)
Px=7y+yz, Py=7x+z, Pz=y+4x
at (2,2,2)
Px=22, Py=16, Pz=10
(22,16,10)
x(t)=(2,2,2)+t(22,16,10)
22(xz)+16(yz)+10(zz)=0
22x+16y+10z96=0
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