1) If A and B are mutually exclusive events with P(A) = 0.3 and P(B) = 0.5, then P(A\cap B)=? 2) An experiment consists of four outcomes with P(E_1)=0

Daniaal Sanchez 2021-06-07 Answered

1) If A and B are mutually exclusive events with P(A)=0.3 and P(B)=0.5, then P(AB)=?
2) An experiment consists of four outcomes with P(E1)=0.2,P(E2)=0.3, and P(E3)=0.4. The probability of outcome E4 is ?
3) If A and B are mutually exclusive events with P(A)=0.3 and P(B)=0.5, then P(AB)=?
4) The empirical rule states that, for data having a bell-shaped distribution, the percentage of data values being within one standard deviation of the mean is approximately
5) If a penny is tossed four times and comes up heads all four times, the probability of heads on the fifth trial is ?

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Expert Answer

lamusesamuset
Answered 2021-06-08 Author has 93 answers

1) Since events are mutually exclusive : P(AB)=0
and P(AB)=P(A)+P(B)P(AB)=0.3+0.50=0.8
2) since sum of all events is 1
P(E4)=10.20.30.4=0.1
3) here sign is missing , instead ? is given in question: if it is P(AB) ; then it is 0
4) percentage of data values being within one standard deviation of the mean is approximately =68
5) probability of heads on the fifth trial is =0.5

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