Find the 37th term of an arithmetic sequence whose second and third terms are −4 and 12. If the fourth term of an arithmetic sequence is 17 and the second term is 3, find the 24th term.

Wierzycaz

Wierzycaz

Answered question

2021-01-15

Find the 37th term of an arithmetic sequence whose second and third terms are −4 and 12. If the fourth term of an arithmetic sequence is 17 and the second term is 3, find the 24th term.

Answer & Explanation

ottcomn

ottcomn

Skilled2021-01-16Added 97 answers

Step 1 Given: Second term (a2)= 4 Third term (a3)=12 Step 2 Used concept Tn=a1 + (n  1)d Where Tn  n(th) term
a1  1(st) term
d  difference =(a2  a1)=(a3  a2) Step 3 Apply the above concept it gives d=a3  a2
d=12  (4)
d=12 + 4=16 now, a1=a2  d
a1= 4  16= 20 Step 4 The 37(th) term of the given arithmetic sequence will be T37= 20 + (37  1) × 16
= 20 + 36 × 16
= 20 + 576
=556 (answer)

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