Find the 37th term of an arithmetic sequence whose second and third terms are −4 and 12. If the fourth term of an arithmetic sequence is 17 and the second term is 3, find the 24th term.

Wierzycaz 2021-01-15 Answered
Find the 37th term of an arithmetic sequence whose second and third terms are −4 and 12. If the fourth term of an arithmetic sequence is 17 and the second term is 3, find the 24th term.
You can still ask an expert for help

Want to know more about Polynomial arithmetic?

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

ottcomn
Answered 2021-01-16 Author has 97 answers
Step 1 Given: Second term (a2)= 4 Third term (a3)=12 Step 2 Used concept Tn=a1 + (n  1)d Where Tn  n(th) term
a1  1(st) term
d  difference =(a2  a1)=(a3  a2) Step 3 Apply the above concept it gives d=a3  a2
d=12  (4)
d=12 + 4=16 now, a1=a2  d
a1= 4  16= 20 Step 4 The 37(th) term of the given arithmetic sequence will be T37= 20 + (37  1) × 16
= 20 + 36 × 16
= 20 + 576
=556 (answer)
Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more