Given the first three terms of an arithmetic progression as 2x, x + 4 and 2x - 6 respectively. Find the value of x and then give the first five terms of this arithmetic sequence.

Albarellak 2020-12-24 Answered
Given the first three terms of an arithmetic progression as 2x, x + 4 and 2x  6 respectively. Find the value of x and then give the first five terms of this arithmetic sequence.
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Expert Answer

Sadie Eaton
Answered 2020-12-25 Author has 104 answers
Step 1 let a1, a2, a3, a4, a5 be the terms of A.P with common difference "d" according to question a1=2x
a2=x + 4
a3=2x  6
d=a2  a1
d=x + 4  2x
d=4  x also d=a3  a2
d=2x  6  x  4
d=x  10
as x  10=4  x
2x=14
x=7 Step 2 so as a1=2x
 a1=14
a2=a1 + d
a2=14  3
a2=11
a3=a2 + d
a3=11  3
a3=8
a4=a3 + d
a4=8  3
a4=5
a5=5  3
a5=2
so 14, 11, 8, 5, 2
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