The bacteria population has an exponential growth with a factor of 18 per hour. The growth factor has to be determined for the population change each half hour.
Step 2
To find the growth factor for every half an hour as follows,
For an exponential function,\( \text{Growth factor of one hour} = (\text{Growth factor of half an hour})^{2}\) K Assuming growth factor of half an hour as x, \(18=x^{2} x=\sqrt{18} x=3\sqrt{2} \)
Hence the growth factor is \(x=3\sqrt{2}\)
A bacteria population is growing exponentially with a growth factor of \(\frac{1}{6}\) each hour.By what growth rate factor does the population change each half hour.Select all that apply
a: \(\frac{1}{12}\)
b: \(\sqrt{\frac{1}{6}}\)
c: \(1/3\)
d: \(\sqrt6\)
e: \(\frac{1}{6}^{\frac{1}{2}}\)
The population of a region is growing exponentially. There were 10 million people in 1980 (when \(t=0\)) and 75 million people in 1990. Find an exponential model for the population (in millions of people) at any time tt, in years after 1980.
P(t)=?
What population do you predict for the year 2000?
Predicted population in the year 2000 =million people. What is the doubling time?
